2Technical information
2.1 Surge protection
The USBLC6-2 is particularly optimized to perform surge protection based on the rail to rail topology.
The clamping voltage VCL can be calculated as follow:
VCL+ = VTRANSIL + VF for positive surges
VCL- = - VF for negative surges
with: VF = VT + Rd.Ip
(VF forward drop voltage) / (VT forward drop threshold voltage)
and VTRANSIL = VBR + Rd_TRANSIL.IP
Calculation example
We assume that the value of the dynamic resistance of the clamping diode is typically:
Rd = 0.5 Ω and VT = 1.1 V
We assume that the value of the dynamic resistance of the transil diode is typically:
Rd_TRANSIL = 0.5 Ω and VBR = 6.1 V For an IEC 61000-4-2 surge level 4 (Contact Discharge: Vg = 8 kV, Rg = 330
Ω), VBUS = +5 V, and if in first approximation, we assume that:
Ip = Vg / Rg = 24 A.
So, we find:
VCL+ = +31.2 V
VCL- = -13 V
Note: The calculations do not take into account phenomena due to parasitic inductances.
2.2 Surge protection application example
If we consider that the connections from the pin VBUS to VCC, from I/O to data line and from GND to PCB GND
plane are done by tracks of 10 mm long and 0.5 mm large, we assume that the parasitic inductances LVBUS, LI/O
and LGND of these tracks are about 6 nH. So when an IEC 61000-4-2 surge occurs on data line, due to the rise
time of this spike (tr = 1 ns), the voltage VCL has an extra value equal to LI/O.dl/dt + LGND.dI/dt.
The dI/dt is calculated as:
dI/dt = Ip/tr = 24 A/ns
The overvoltage due to the parasitic inductances is:
LI/O.dl/dt = LGND.dI/dt = 6 nH x 24 A/ns = 144 V
By taking into account the effect of these parasitic inductances due to unsuitable layout, the clamping voltage will
be:
VCL+ = +31.2 + 144 + 144 = 319.2 V
VCL- = -13.1 - 144 - 144 = -301.1 V
We can significantly reduce this phenomena with simple layout optimization. It is for this reason that some
recommendations have to be followed (see ).
USBLC6-2
Technical information
DS4260 - Rev 6 page 4/21